Given below the cross-section details of the single-room building.

Based on the above details the following 5 building estimation quantities for the single room shall be calculated.

- Earthwork excavation quantity for the foundation
- Concrete quantity for the foundation
- CRS (crushed rouble stone) masonry quantity
- Concrete quantity in plinth beams
- 1st class brickwork in single room building superstructure.

The longwall length from centre to the centre can be calculated =6+0.5×0.230+0.5x.230=6.23 m

The short wall length from centre to the centre can be calculated =5+0.5×0.230+0.5×0.230=5.23 m.

### 1.Earthwork excavation quantity in foundation :

From the single-room building section, depth of foundation from ground level(GL) is 900mm (300 mm +300 mm+300 mm) and width of the foundation is 900 mm.

Total length of one long wall for foundation excavation = 6.23 m+0.45 m+0.45 m = 7.13 m

The total length of one short wall for foundation excavation =5.23 m- 0.45 m -0.45 m =4.33 m.

So, total earthwork excavation quantity in foundation for long walls = 2 nos x 7.13 m x 0.9 m depth x 0.9 m width =11.55 cum

Total earthwork excavation quantity in foundation for short walls = 2 nos x 4.33 m x 0.9m depth x 0.9 m width = 7.01 cum.

So Total building estimation item, earthwork excavation quantity for the foundation of single-room building = 11.55 cum + 7.01 cum =18.56 cum.

### 2.Concrete quantity for the foundation :

Total length of one long wall for foundation Concrete = 6.23 m+0.45 m +0.45 = 7.13 m

The total length of one short wall for foundation Concrete =5.23 m-0.45 m-0.45 m=4.33 m

From the single-room building section, depth of concrete foundation is 0.3 m.

So, total concrete quantity for foundation for long walls = 2 nos x 7.13 m x 0.3 m depth x 0.9 m width =3.85 cum

Total concrete quantity for foundation for short walls = 2 nos x 4.33 m x 0.3 m depth x 0.9 m width =2.33 cum

Total building estimation item, concrete quantity for foundation is 3.85 cum + 2.33 cum =6.18 cum.

### 3.Crushed rubble stone masonry quantity

As per the single-room building section, CRS masonry is laid in 2 steps.

In 1st step crushed rubble stone ( CRS) wall width is 600 mm and height is 300 mm.

In the 2nd step, CRS wall width is 500 mm and the depth is 300 mm.

#### 1st step CRS wall

##### Long CRS wall

The total length of one long CRS wall in 1st step = 6.23 m+0.3 m + 0.3 m =6.83 m

So Total long CRS wall quantity in 1st step=2 nos x 6.83 m x 0.6 m x 0.3 m = 2.45 cum

##### Short CRS wall

The total length of short CRS wall in 1st step = 5.23 m – 0.3 m -0.3 m =4.63 m.

Total short CRS wall quantity in 1st step =2 nos x 4.63 m x 0.6 m x 0.3 m = 1.66 cum

#### 2nd step CRS wall

##### Long CRS wall

The total length of one long CRS wall in 2nd step = 6.23 m+0.25 m + 0.25 m =6.73 m

So Total long CRS wall quantity in 2nd step=2 nos x 6.73 m x 0.5 m x 0.3 m = 2.01 cum

##### Short CRS wall

The total length of short CRS wall in 2nd step = 5.23 m – 0.25 m -0.25 m =4.73 m.

Total short CRS wall quantity in 2nd step =2 nos x 4.73 m x 0.5 m x 0.3 m = 1.41 cum

#### Total CRS masonry quantity

So Total building estimation items, CRS masonry quantity for building including 1st and 2nd step =2.45 cum +1.66 cum +2.01 cum + 1.41 cum =7.53 cum.

### 4.Concrete quantity in plinth beams

As per the section, the depth of the plinth beam is 600 mm and width is 400 mm.

#### Long plinth beam

The total length of long plinth beam = 6.23 m+0.20 m + 0.20 m =6.63 m

So Total long plinth beam concrete quantity =2 nos x 6.63 m x 0.4 m x 0.6 m = 3.18 cum

#### Short plinth beam

The total length of short plinth beam = 5.23 m – 0.20 m -0.20 m =4.83 m.

Total short plinth beam concrete quantity =2 nos x 4.83 m x 0.4 m x 0.6 m = 2.31 cum

#### Total plinth beam quantity

So Total building estimation item, plinth beam concrete quantity for building=3.18 cum +2.31 cum =5.49 cum

### 5.1st class brickwork in the superstructure

As per the given section, the brick wall thickness is 230 mm and height is 3.5 m.

#### Long brick wall

The total length of long brick wall =6.23 m+0.115 m + 0.115 m =6.46 m

So Total long wall brickwork quantity =2 nos x 6.46 m x 0.23 m width x 3.5 m height = 10.4 cum

#### Short brick wall

The total length of short brick wall = 5.23 m – 0.115 m -0.115m =5 m.

Total short wall brickwork quantity =2 nos x 5 m x 0.23 m x 3.5 m = 8.05 cum

#### Total 1st class brickwork quantity

So Total building estimation items, 1st class brickwork quantity for building=10.4 cum +8.05 cum =18.9 cum

### Conclusion :

So by the above process, we can calculate 5 building estimation items of one single room.

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