RCC Column cast in the foundation footing cost estimation can be estimated from the provided plan, section drawings, local work rates.
RCC Column specification, plan and section details
- Footing size is 2 m length x 2 m wide x 0.45 m depth
- PCC 1:4:8 is utilised in foundation
- RCC 1:2:4 is utilised in footing
- 300 dia is the column size above plinth level,350 mm x 350 mm is the size from footing top-level to plinth level and the RCC 1:2:4 is utilised,
- Reinforcement 12 mm dia @150 mm c/c both sides is utilised in footing
- Main bars 6 numbers 16 mm dia and stirrups 10mm dia @ 150 mm c/c is utilised in the column.
RCC column quantity, cost estimation
The following 6 steps are involved in the estimation
- In foundation earthwork excavated quantity estimation.
- PCC quantity estimation in foundation quantity.
- RCC quantity estimation in the footing
- RCC quantity estimation in column
- Reinforcement quantity estimation in footing and column
- Total cost estimation of all works
1. In foundation earthwork excavated quantity estimation
From the above-mentioned section depth of foundation excavated=0.83m.From specifications and plan length of foundation is 2 m and width is 2 m.
Earthwork excavated quantity can be estimated by=2 m length x2 m wide x 0.83 m depth=3.32 cum.
2. PCC quantity estimation in foundation quantity.
From the section, the depth of PCC in the foundation is 80 mm. From the plan length of the foundation is 2 m and the width is 2 m.
Plain cement concrete, PCC 1:4:8 is utilised in the foundation.
PCC quantity can be estimated by=2 m length x 2 m width x 0.08 m depth=0.32 cum.
3. RCC quantity estimation in the footing
RCC 1:2:4 is utilised in footing.
From the section length of footing is 2 m, width of footing is 2 m and depth is 0.45 m
RCC quantity in footing can be calculated by = 2 m x 2 m x 0.45 m =1.8 cum.
Single room |5 building estimation items
4. RCC quantity estimation in column
RCC 1:2:4 is utilised. From the specifications,300 dia is the size and 3.3 m is the height from plinth level to slab bottom,350 mm x 350 mm is the size and height 900 mm from footing top-level to plinth level.
Quantity from footing top-level to plinth level
Concrete quantity from footing top-level to plinth level can be calculated by =0.35 m x 0.35 m x 0.9 m=0.11 cum
Quantity from footing plinth level to slab bottom
Concrete quantity from plinth top-level to slab bottom level can be calculated by =3.14 x (0.3 m x 0.3 m )/4x 3.3 m=0.233 cum
So, the total concrete quantity =0.11 cum + 0.233 cum=0.343 cum
5. Reinforcement quantity estimation in footing and column
From specifications, Reinforcement 12 mm dia @150 mm c/c both sides is utilised in footing.
Main bars 6 numbers 16 mm dia and stirrups 10mm dia @ 150 mm c/c is utilised
Reinforcement quantity in footing
Length of the footing is 2 m and width is 2 m, clear cover =40mm
No. of bars =(clear length/spacing) +1
Clear length=total length-2 x clear cover=2 m-2 x 0.04m=1.92 m
Total No.of bars along the length of footing=(1.92/0.15)+1= 14 bars.
Similarly, Total No.of bars along the width of footing=(1.92/0.15)+1= 14 bars.
The total length of steel bar=length-2x clear cover +20 x dia.steel=2 m -2 x 0.04+ 20×0.012=2.16 m.
Unit Weight of steel= (steel dia x steel dia) /162= 12 x 12/162=0.89 kg/m
Total weight of steel quantity in footing can be calculated by=2 ways x No’s of bars x total steel length x unit weight of steel
=2 x 14 no’s x 2.16 m x 0.89 kg/m =53.82 kgs
Reinforcement quantity in column from footing to slab bottom
Length is 300 mm dia, clear cover =40mm
Main bars weight
No. of main bars =6 no’s
Total length of bar from footing to slab bottom =0.45 m+0.3 m +bottom bent-clear cover+0.6 m+3.3 m+top bent=0.45+0.3+0.15-0.08+0.6+3.3+0.1=4.89 m
Unit weight =dia x dia/162=16 x 16/162=1.58 kg/m
Total weight of main bars =No.of bars x total length x unit weight=6No’s x 4.89 m x 1.58 kg/m=46.35 kgs
For stirrups 10mm dia @ 150 mm c/c is utilised.
Length in which stirrups is utilised =3.3 m +0.6 m +0.3 m=4.2m
No. of bars =(clear length/spacing) +1
So, No of bars=(4.2/0.15)+1=29 no’s
Clear length of bar=3.14 x (total dia-2 x clear cover)=3.14 x (0.3 m-2 x 0.04m)=0.7 m
Unit Weight of steel= (steel dia x steel dia) /162= 10 x 10/162=0.62 kg/m
Total weight of steel quantity in stirrups can be calculated by= No’s of bars x total steel length x unit weight of steel
= 29 no’s x 0.7 m x 0.62 kg/m =12.58 kgs
So,total weight of steel in footing and column=53.82 kgs +46.35 kg +12.58 kg=112.75 kg=0.112 MT
6. Total cost estimation of all works
For total cost estimation,local rates which includes material and labour are considered for all works.
Rate of cement concrete includes material and labour cost of shuttering but excludes steel material and labour cost are considered in the cost estimation.
Rate of steel includes material and labour charges are considered in cost estimation.
|S.No||Description of work||Quantity||Rate||Amount|
|1||In foundation excavated earth||3.32 cum||Rs.350||Rs.1162|
|2||PCC in foundation||0.32 cum||Rs.3200||Rs.1024|
|3||Cement concrete in footing||1.8 cum||Rs.3800||Rs.6840|
|4||Cement concrete in column||0.343 cum||Rs.4400||Rs.1509.2|
|5||Reinforcement in footing and columns||0.112 MT||Rs.10200||Rs.1142.4|
|5% contigency is added||Rs.12261.48|
So from the above steps cost estimation can be calculated very easily.
Double room building estimation|6 steps
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