Double room building estimation can be calculated by estimating earthwork in excavation,foundation concrete,plinth beam,1st class brickwork, cement concrete quantity.
Double room building estimation specifications, drawings
The following are the double room building estimation specifications
- In foundation cement concrete M25 is utilised.
- CRS wall is utilised in the foundation for the base of the brick wall.
- Plinth beam 400 mm x 600mm is utilised in cement concrete M25
- Dampproof course 25mm thick is applied.
- In superstructure 1st class brickwork in 1:4 cement mortar and thickness 300mm is utilised.
- Doors D ,size-1.2 m x 2.1 m
- windows W,size-1 m x 1.5 m,Shelves S-1 m x 1.5 m
Double room building estimation in 6 steps
The following building estimation 7 steps for a double room.
- In foundation excavated earth quantity,
- In foundation cement concrete quantity,
- CRS wall in the foundation quantity,
- Plinth beam quantity
- Dampproof course quantity,
- In superstructure 1st class brickwork quantity
Note: This building estimation is only limited up to brick walls quantity in the superstructure.
Length of the long wall from centre to centre =4 m + 6 m + 0.3 m+0.5×0.3 m +0.5×0.3 m=10.6 m
length of short walls from centre to centre = 6 m +0.5×0.3 m +0.5×0.3 m=6.3 m
1.Excavated earth quantity in foundation
Longwall length of excavated earth in foundation can be calculated by =10.6 m +0.5 x 1.1 m +0.5×1.1 m=11.7 m
Short wall length of excavated earth in foundation can be calculated by =6.3 m -0.5×1.1 m-0.5×1.1 m=5.2 m
| S.No | Description of work | No | Length(m) | Breadth(m) | Depth/Height | Quantity |
| 1 | Excavated earth quantity in foundation | |||||
| Long wall quantity | 2 | 11.7 m | 1.10 m | 1 m | 25.74 cum | |
| Short wall quantity | 3 | 5.2 m | 1.10 m | 1 m | 17.16 cum | |
| Total quantity | 42.9 cum |
2.Cement concrete quantity in foundation
Longwall length of cement concrete earth in foundation can be calculated by =10.6 m +0.5 x 1.1 m +0.5×1.1 m=11.7 m
Short wall length of cement concrete in foundation can be calculated by =6.3 m -0.5×1.1 m-0.5×1.1 m=5.2 m
| S.No | Description of work | No | Length(m) | Breadth(m) | Depth/Height | Quantity |
| 2 | Cement concrete quantity in foundation | |||||
| Long wall quantity | 2 | 11.7 m | 1.10 m | 0.3 m | 7.72 cum | |
| Short wall quantity | 3 | 5.2 m | 1.10 m | 0.3 m | 5.15 cum | |
| Total quantity | 12.87 cum |
3.CRS wall quantity in foundation
Long wall length of CRS wall in foundation
In 1st footing can be calculated by =10.6 m +0.5 x 0.8 m +0.5 x 0.8 m=11.4 m
In 2nd footing can be calculated by =10.6 m +0.5 x 0.7 m +0.5 x 0.7 m=11.3 m
In 3rd footing can be calculated by =10.6 m +0.5 x 0.6 m +0.5 x 0.6 m=11.2 m
In 4th footing can be calculated by =10.6 m +0.5 x 0.5 m +0.5 x 0.5 m=11.1 m
Short wall length of CRS wall in foundation
In 1st footing can be calculated by =6.3 m -0.5 x 0.8 m -0.5 x 0.8 m=5.5 m
In 2nd footing can be calculated by =6.3 m -0.5 x 0.7 m -0.5 x 0.7 m=5.6 m
In 3rd footing can be calculated by =6.3 m -0.5 x 0.6 m -0.5 x 0.6 m=5.7 m
In 4th footing can be calculated by =6.3 m -0.5 x 0.5 m -0.5 x 0.5 m=5.8 m
| S.No | Description of work | No | Length(m) | Breadth(m) | Depth/Height | Quantity |
| 3 | CRS wall quantity in foundation | |||||
| Long wall quantity | ||||||
| 1st footing quantity | 2 | 11.4 m | 0.8 m | 0.2 m | 3.65 cum | |
| 2nd footing quantity | 2 | 11.3 m | 0.7 m | 0.1 m | 1.58 cum | |
| 3rd footing quantity | 2 | 11.2 m | 0.6 m | 0.1 m | 1.34 cum | |
| 4th footing quantity | 2 | 11.1 m | 0.5 m | 0.1 m | 1.11 cum | |
| Short wall quantity | ||||||
| 1st footing quantity | 3 | 5.5 m | 0.8 m | 0.2 m | 2.64 cum | |
| 2nd footing quantity | 3 | 5.6 m | 0.7 m | 0.1 m | 1.18 cum | |
| 3rd footing quantity | 3 | 5.7 m | 0.6 m | 0.1 m | 1.03 cum | |
| 4th footing quantity | 3 | 5.8 m | 0.5 m | 0.1 m | 0.87 cum | |
| Total quantity | 13.4 cum |
4.Dampproof course quantity
25 mm thick damp proof course is laid and considered in building estimation.
Longwall length for damp proof course can be calculated by =10.6 m +0.4 x 0.5 m +0.4×0.5 m=11 m
Short wall length for damp proof course can be calculated by =6.3 m -0.5×0.4 m-0.5×0.4 m=5.9 m
| S.No | Description of work | No | Length(m) | Breadth(m) | Depth/Height | Quantity |
| 4 | Damp proof course quantity | |||||
| Long wall quantity | 2 | 11.0 m | 0.4 m | 8.80 Sq.m | ||
| Short wall quantity | 3 | 5.9 m | 0.4 m | 7.08 Sq.m | ||
| Deduct door sills quantity | 2 | 1.2 m | 0.4 m | -0.96 Sq.m | ||
| Total quantity | 14.92 Sq.m |
5.Plinth beam quantity
Longwall length of plinth beam can be calculated by =10.6 m +0.4 x 0.5 m +0.4 x 0.5 m=11 m
Short wall length of plinth beam can be calculated by =6.3 m -0.5 x 0.4 m-0.5 x 0.4 m=5.9 m
| S.No | Description of work | No | Length(m) | Breadth(m) | Depth/Height | Quantity |
| 5 | Plinth beam quantity | |||||
| Long wall quantity | 2 | 11.0 m | 0.4 m | 0.8 m | 7.04 cum | |
| Short wall quantity | 3 | 5.9 m | 0.4 m | 0.8 m | 5.66 cum | |
| Total quantity | 12.7 cum |
6.1st class brick work quantity in superstructure
1st class brick work is laid in 1:4 cement mortar with 300 mm thick in building estimation is used.
Center to center Long-wall length of brick wall can be calculated by =10.6 m +0.3 x 0.5 m +0.3 x 0.5 m=10.9 m
Center to center Short wall length of plinth beam can be calculated by =6.3 m -0.3 x 0.4 m-0.3 x 0.4 m=6 m
| S.No | Description of work | No | Length(m) | Breadth(m) | Depth/Height | Quantity |
| 6 | 1st class brick work quantity in super structure | |||||
| Long wall quantity | 2 | 10.9 m | 0.3 m | 4.2 m | 27.42 cum | |
| Short wall quantity | 3 | 6 m | 0.3 m | 4.2 m | 22.68 cum | |
| Deductions | ||||||
| Door openings quantity | 2 | 1.2 m | 0.3 m | 2.1 m | 1.51 cum | |
| window openings quantity | 4 | 1 m | 0.3 m | 1.5 m | 1.80 cum | |
| Shelves quantity | 2 | 1 m | 0.2 m | 1.5 m | 0.6 cum | |
| Lintels over doors quantity | 2 | 1.5 m | 0.3 m | 0.15 m | 0.14 cum | |
| Lintels over windows quantity | 4 | 1.3 m | 0.3 m | 0.15 m | 0.23 cum | |
| Lintels over shelves quantity | 2 | 1.3 m | 0.3 m | 0.15 m | 0.12 cum | |
| Total quantity | 45.75 cum |
Conclusion
So from the above 6 steps double room building estimation up to brick wall in superstructure can be done easily.
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